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A particle moving along y–axis is at y = 5 cm at t = 0 (where t is in second). This particle is observed to trace the following velocity time graph.

The displacement y of this particle in terms of t can be written as

(1) y = 5 – 2t + 8t2

(2) t = 2t2 – 8t + 5

(3) y = 8t2 –2t – 5

(4) y = 5 – 4t + 2t2

1 Answer

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Best answer

(2) t = 2t2 – 8t + 5

Given, y(0) = +5m. From the graph,

Velocity = –8 ms-1 at t = 0

∴ v(0) = -8 ms-1

Now, v – t graph is a straight line. Therefore acceleration is a constant a = slope of v vs t graph.

= + 8/2 = +4 ms-2

The final position at t = t can be written as

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