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A stationery body of mass 3 kg explodes in to three equal pieces. One of the pieces flies off with a velocity of 3\(\hat{i}\) ms-1 and a second one goes with velocity of 4\(\hat{j}\) ms-1. If the time of explosion is 10-4s, the magnitude of the average force experienced by the third piece is

(1) 70 kilo newton

(2) 50 kilo newton

(3) 40 kilo newton

(4) 30 kilo newton

1 Answer

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Best answer

(2) 50 kilo newton

The momentum imparted to the two pieces together is:

As the body of 3 kg is initally at rest the change in momentum for the third piece should be equal and opposite that for the first two taken together.

Time taken for this change, Δt = 10-4 s

∴ Force on the third piece is

= 50 x 103 N = 50 Kilo newton

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