Question

The position ‘x’ of a particle varies with time ‘t’ as : x = mt²–nt³ . The acceleration time graph of this particle is

Answer 1

Correct option is (4)

Given : x = mt² – nt³ .

Eqn. (ii) is of the form y = mx + c for the equation of a straight line, where m is slope and c is y intercept. 

Hence a – t graph is a straight line with

(i) slope of –6m.

(ii) of-intercept = +2m and

(iii) a = 0 at t = 2m/6n = m/3n

(i), (ii) and (iii) are true only for (1)