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y = sinx logx dy/dx = ?

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y = sinx logx dy/dx = ?

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1 Answer

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Applying the u.v rule,

d/dx(sinx). logx + sinx. d/dx(logx) 

= cosx.logx + sinx. x

y = d/dx (sinx.logx) 

= sinx.1/x + logx.cosx sinx/x + logx.cosx

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