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A system of two blocks, of masses m1 and m2 , a smooth inclined plane, a light pulley and an inextensible light string, arranged as shown, is observed to be in equilibrium. If the normal reaction, due to the inclined plane, on the mass m1 equals that due to a mass M, on a horizontal surface, we would have

(1) M =\(\sqrt{m^2_1+m^2_2}\)

(2) M = \(\sqrt{m^2_1-m^2_2}\) 

(3) M = (m1 sinα m2)

(4)  M = (m1 cosα m2)

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(2) M = \(\sqrt{m^2_1-m^2_2}\) 

The free body diagrams, for the masses m1 and m2 , are as shown. Since the system is in equilibrium (i.e. has zero acceleration), we have

m2 g - T = 0  .....(1)

and N m1 g cos α  .....(2)

and T - m1 g sin α =  .....(3)

Adding (1) & (3)

For the mass m1 on the horizontal surface, we have

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