Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
68 views
in Physics by (51.7k points)
closed by

A soap bubble of radius r is formed in air. Excess pressure inside bubble is p. The bubble is now kept inside a soap solution. Assuming there is no change in its size; the excess pressure is 

(a) p 

(b) 2p 

(c) p/2 

(d) 3/2 p

1 Answer

+1 vote
by (52.1k points)
selected by
 
Best answer

(c) p/2 

Soap bubble in air has two free surfaces. Excess pressure = P = 4s/r

Inside soap solution: the same bubble has only one free surface.

The excess pressure = p' = 2S/r = p/2.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...