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0 votes
125 views
in Algebra by (53.6k points)

If a + b + c = 1, then find k such that

\(\frac k{27abc} > (\frac 1a -1)(\frac 1b -1) (\frac 1c -1)>k\)

a. 8

b. 7

c. 3

d. none of these

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1 Answer

+1 vote
by (53.4k points)

Correct option is a. 8

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