If x, y, z > 0 and x + y + z = 1, the xyz/(1-x)(1-y)(1-z) is necessarily

Question

If x, y, z > 0 and x + y + z = 1, the \(\frac{xyz}{(1-x)(1-y)(1-z)}\) is necessarily

(a) ≥ 8

(b) ≤ 1/8

(c) < 1/8

(d) None of these

Answer 1

Correct option is (b) ≤ 1/8