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If (1^2 – t1) + (2^2 – t2) + ............. + (n^2 – tn) = n/3 (n^2 – 1), then tn is equal to

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in Algebra by (53.6k points)

If (12 – t1) + (22 – t2) + ............. + (n2 – tn) = n/3 (n2 – 1), then tn is equal to

(a) n2

(b) 2n

(c) n2 – 2n

(d) None of these

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1 Answer

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by (53.3k points)

Correct option is (d) None of these

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