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+1 vote
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in Straight Lines by (51.0k points)

A(1, 3) and \(C(-\frac 25,-\frac 25)\) are the vertices of a triangle ABC and the equation of the angle bisector of ∠ABC is x + y = 2

1. Equation of side BC is

(a) 7x + 3y = 4

(b) 7x + 3y + 4 = 0

(c) 7x – 3y + 4 = 0

(d) 7x – 3y = 4

2. Coordinates of vertex B are

(a) \((\frac3{10}, \frac{17}{10})\)

(b) \(( \frac{17}{10},\frac3{10})\)

(c) \((-\frac 52, \frac 92)\)

(d) (1, 1)

3. Equation of side AB is

(a) 3x + 7y = 24

(b) 3x + 7y + 24 = 0

(c) 13x + 7y + 8 = 0

(d) 13x – 7y + 8 = 0

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1 Answer

+1 vote
by (51.3k points)

1. (b) 7x + 3y + 4 = 0

2. (c) \((-\frac 52, \frac 92)\) 

3. (a) 3x + 7y = 24

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