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in Circles by (51.0k points)

Equation of the normal to the circle x2 + y2 – 4x + 4y – 17 = 0 which passes through (1, 1) is

a. 3x + 2y – 5 = 0

b. 3x + y – 4 = 0

c. 3x + 2y – 2 = 0

d. 3x – y – 8 = 0

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1 Answer

+1 vote
by (51.3k points)

b. 3x + y – 4 = 0

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