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0 votes
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in Circles by (51.0k points)
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The shortest distance from the point (2, –7) to the circle x2 + y– 14x – 10y – 151 = 0 is

a. 1

b. 2

c. 3

d. 4

2 Answers

+1 vote
by (51.3k points)
selected by
 
Best answer

Correct option is b. 2

\(P(-7, 2)\)

\(x^2 + y^2 - 10x - 14y - 151 = 0\)

\(C(-g, -y) = C(5, 7)\)

\(C = -151\)

\(r = \sqrt{5^2 + 7^2} - (-51) = 15\)

\(P(-7, 2), C(5, 7)\)

\(CP = \sqrt{(5 +7)^2 + (7 -2)^2} =13\)

The shortest distance

\(r - CP\)

\(= 15 - 13 = 2\)

+1 vote
by (105 points)

imagecorrect option is B sorry  because of writing C 9in Answers 

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