Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
78 views
in Circles by (51.4k points)
edited by

The equation of the image of the circle (x–3)+ (y–2)2 = 1 by the mirror x + y = 19 is

a. (x–14)2 + (y–13)2 = 1

b. (x–15)2 + (y–14)2 = 1

c. (x–16)2 + (y–15)2 = 1

d. (x–17)+ (y–16)2 = 1

Please log in or register to answer this question.

1 Answer

+1 vote
by (51.1k points)

d. (x–17)2 + (y–16)2 = 1

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...