Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
369 views
in Binomial Theorem by (51.3k points)

\(\sum\limits_{r=0}^n(-1)^r \,^nC_r \left( \frac 1{2^r} + \frac{3^r}{2^{2r}} + \frac {7^r}{2^{3r}}+\frac{15^r}{2^{4r}} + ....\text{up to m terms}\right) =\)

(a) \(\frac{2^{mn}-1}{2^{mn} (2^n - 1)}\)

(b) \(\frac{2^m-2^n}{m-n}\)

(c) 1

(d) None of these

Please log in or register to answer this question.

1 Answer

+1 vote
by (51.0k points)

Correct option is (a) \(\frac{2^{mn}-1}{2^{mn} (2^n - 1)}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...