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+1 vote
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in Binomial Theorem by (51.0k points)

The coefficient of x8 is the expansion of \(\left(1 + \frac{x^2}{2!} + \frac{x^4}{4!}+ \frac{x^6}{6!} + \frac{x^8}{8!}\right)^2\) is

(a) \(\frac 1{315}\)

(b) \(\frac 2{315}\)

(c) \(\frac 1{105}\)

(d) \(\frac 1{210}\)

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1 Answer

+1 vote
by (51.3k points)

Correct option is (a) \(\frac 1{315}\)

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