Correct option: (A) 50
Explanation:
ΔQ = n ∙ CP ∙ ΔT…..as gas is heated at constant pressure from given data, n = 2 moles & ΔQ = 70 cal
∴ 70 = 2 × CP × (35 – 30)
∴ CP = 7 cal/g mol/°C
As Cp – Cv = R
∴ Cv = Cp – R = 7 – 2 = 5 cal/g mol/°C
∴ as ΔQ = n CV ΔT……To heat gas at constant volume
∴ ΔQ = 2 × 5 × (35 – 30) = 50 cal