Let A (a) and B(b) be points on two skew lines r = a + λp and r = b + µq and the shortest distance between the skew lines is 1, ​

Question

Let A (\(\vec a\)) and B(\(\vec b\)) be points on two skew lines \(\vec r = \vec a+ \lambda\vec p\) and \(\vec r = \vec b+ \mu\vec q\) and the shortest distance between the skew lines is 1, where \(\vec p\) and \(\vec q\) are unit vectors forming adjacent sides of a parallelogram enclosing an area of 1/2 sq.units. If an angle between AB and the line of shortest distance is 60°, then AB =

(a) 1/2

(b) 2

(c) 1

(d) None of these

Answer 1

Correct option is (b) 2