Question

If γ is the ratio of Specific heats and R is the universal gas constant, then the molar Specific heat at constant Volume C_v is given by 

(A) {( γ R) / (v – 1)} 

(B) γ R 

(C) {R / (γ – 1)} 

(D) [{(γ – 1)R} / r]

Answer 1

Correct option: (C) {R / (γ – 1)}

Explanation:

C_P – C_V = R where R is universal gas constant

Also (C_P / C_V) = γ    i.e.      C_P = γ C_V 

Hence   γC_V – C_V = R

∴  C_V(γ – 1) = R

∴  C_V = [R / (γ – 1)]