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An ideal heat engine working between temperature T1 and T2 has an efficiency η.

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An ideal heat engine working between temperature T1 and T2 has an efficiency η. The new efficiency if both the source and sink temperature are doubled, will be 

(A) η 

(B) 2η 

(C) 3η 

(D) (η / 2)

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1 Answer

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Correct option: (A) η

Explanation:

η = 1 – (T2 / T1)……… for ideal heat engine

If both temperature are doubled, ratio (T2 / T1) will remain same hence efficiency is η again.

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