If |{1+a 1 1} {1+b 1+2b 1} {1+c 1+c 1+3c}| = 0 where a ≠ 0, b ≠ 0, c ≠ 0, then a^–1 + b^–1 + c^–1 =

Question

If \(\begin{vmatrix}1+a&1&1\\1+b&1+2b&1\\1+c&1+c&1+3c \end{vmatrix}=0\) where a ≠ 0, b ≠ 0, c ≠ 0, then a^–1 + b^–1 + c^–1 =

(a) 4

(b) –3

(c) –2

(d) –1

Answer 1

Correct option is (b) –3