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In Fig., 4.221, ∠B < 90° and segment AD ⊥ BC, show that

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In Fig., 4.221, ∠B < 90° and segment AD ⊥ BC, show that

(i) b2=h2+a2+x2-2ax

(ii) b2=a2+c2-2ax

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In ΔADC, by pythagoras theorem

by Pythagoras theorem

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