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0 votes
2.0k views
in Mathematics by (2.8k points)
The maximum value of 5a for which four normals can be drawn to ellipse x^2/25+y^2/16=1 through a point (a,0) is

a)7

b)9

c)5

d)6

1 Answer

+1 vote
by (1.4k points)
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Best answer

Hi, I am getting this on solving

Equation for normal to eclipse is given by

5x/cosm-4y/sinm=9

It passes through point (a,0)

so, 5a/cosθ-4*0/sinθ=9

5a=9cosθ

a = 9cosθ/5

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