# If 6 and -2 be the zeroes of a quadratic polynomial p(x) = x^2 + bx + c then the values of b and c are respectively

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If 6 and -2 be the zeroes of a quadratic polynomial p(x) = x2 + bx + c then the values of b and c are respectively

(A) 4, 12

(B) -4, 12

(C) 4, -12

(D) -4, -12

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Correct option is (D) -4, -12

Sum of roots = $\frac{-b}1 = -b$

⇒ $-b = 6 + (-2) = 4$

⇒ $b = -4$

Product of roots = $\frac c1 = c$

⇒ $c=6 \times -2 = -12$