Question

If 6 and -2 be the zeroes of a quadratic polynomial p(x) = x² + bx + c then the values of b and c are respectively

(A) 4, 12

(B) -4, 12

(C) 4, -12

(D) -4, -12

Answer 1

Correct option is (D) -4, -12

Sum of roots = \(\frac{-b}1 = -b\) 

⇒ \(-b = 6 + (-2) = 4\)

⇒ \(b = -4\)

Product of roots = \(\frac c1 = c\)

⇒ \(c=6 \times -2 = -12\)