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Prove that (1+cotA+tanA)(sinA-cosA)=secA/cosec^2A-cosecA/sec^2A=sinAtanA-cosAcotA

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Prove that (1+cotA+tanA)(sinA-cosA)=secA/cosec2A-cosecA/sec2A=sinAtanA-cosAcotA

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Best answer

  L.H.S = R.H.S

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thank you , it helped a lot.
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(cos 0° + sin 45° + sin 30°)(sin 90° − cos 45° + cos 60°) …(i)
By trigonometric ratios we have

By substituting above values in (i), we get

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`(cosecA-sinA)(secA-cosA)(tanA+cotA)` = __________.
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