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0 votes
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in Physics by (44.7k points)

The nucleus which has radius one third of the radius of OS189 is

(A) Be9

(B) F19

(C) C12

(D) Li7

1 Answer

+1 vote
by (69.7k points)
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Best answer

The correct option is (D) Li7.

Explanation:

R = Ro ∙ A(1/3) ------ Bohr's radius

when A = 189 then R = Ro A(1/3) i.e. R = Ro(189)(1/3)      (1)

 when R = (R / 3) then (R / 3) = Ro(A)(1/3)                 (2)

∴ from (1) & (2) 

[R / (R / 3)] = [(189) / A](1/3) 

∴ (3)3­­ = [(189) / A] 

∴ A = [(189) / (27)] = 7 

∴ nucleus is Li7

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