Question

If the equation for displacement of two particles executing S.H.M. is given by y₁ = 2sin(10t + θ) and y₂ = 3cos10t respectively, then the phase difference between the velocity of two particles will be ………. 

(A) – θ 

(B) θ 

(C) θ – (π/2) 

(D) θ + (π/2).

Answer 1

The correct option (C) θ – (π/2)

Explanation:

y₁ = 2sin(10t + θ)

v₁ = (dy₁/at) = 2 cos(10t + θ) × 10 = 20cos(10t + θ)

y₂ = 3cos10t

v₂ = (dy₂/at) = 30 (– sin10t)

= 30cos{10t + (π/2)}

phase difference = (10t + θ) – {10t + (π/2)}

= θ – (π/2)