Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
147 views
in Chemistry by (54.8k points)
closed by

The number of atoms in 100g of the fcc crystal with density = 10 g/cm3, and the cell edge equal to 200 pm is equal to:

(a) 5 × 1024
(b) 5 × 1025
(c) 6 × 1023
(d) 2 × 1025

1 Answer

+1 vote
by (57.0k points)
selected by
 
Best answer

Correct option is (a) 5 × 1024

Thus 12g of the atom contain = 6.023 × 1023 atom.

∴ 100g of the atom will contain

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...