Question

Electrolysis of dilute aqueous solution of NaCl solution was carried out by passing 10 milliampere current. The time required to liberate 0.01 mole of H₂ gas at the cathode is (1 Faraday = 96500 C mol^-1):

(a) 9.65 × 10⁴ sec
(b) 19.3 × 10⁴ sec
(c) 28.95 × 10⁴ sec
(d) 38.6 × 10⁴ sec

Answer 1

Correct option is (b) 19.3 × 10⁴ sec

Thus,

0.5 mol of H₂ is liberated by IF = 96500 C 0.01 mol of H₂ will be liberated by charge