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Resistance of 0.2 M solution of an electrolyte is 50Ω. The specific conductance of the solution is 1.3 Sm-1. If the resistance of 0.4M solution of the same electrolyte is 260Ω the molar conductivity is:

(a) 6250 Sm2 mol-1
(b) 6.25 × 10-4 Sm2 mol-1
(c) 625 × 10-4 Sm2 mol-1
(d) 62.5 Sm2 mol-1

1 Answer

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Best answer

(b) 6.25 × 10-4 Sm2 mol-1

specific conductance = observed conductance × cell constant

K = 1/R × cell constant

or cell constant = K × R

= 1.3 Sm-1 × 50Ω

= 65 m-1

For 0.4 M solution, specific conductance

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