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 A solution of copper sulfate is electrolyzed for 10 minutes with a current of 1.5 amperes. The mass of copper deposited at the cathode is: (atomic mass of Cu = 63.5 g mol-1)

(a) 29.6 g
(b) 0.296 g
(c) 2.96 g
(d) 1.564 g

1 Answer

+2 votes
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Best answer

Correct option is (b) 0.296 g

Current = 1.5 amperes

Time = 10 minutes

= 10 × 60 = 600 s

Quantity of electricity passed = i × t

= 1.5 × 600 = 900 C

The reaction occurring at cathode is

Cu2+ + 2e → Cu

i.e., 2F or 2 × 96500 C deposit

= 1 mol = 63.5 g of Cu

900 C will deposit = \(\frac{63.5}{2\times 96500} \times 900\) = 0.296 g

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