Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
788 views
in Physics by (15 points)
A wire of resistance 2 ohms per meter is bent to form a circle of radius 1m. The equivalent resistance between its two diametricaly opposite points is

Please log in or register to answer this question.

1 Answer

0 votes
by (69.7k points)

When a resistance is bent in a circle, the resistors are are connected in parallel.

Each of the resistors (the 2 parallel resistors of the circle) have a resistance of 2 ohms.

So we get the following-

Req = R1 x R2 / R1R2 (where Req is equivalent resistance in parallel connections)  

OR  

1/Rp =1/R1 + 1/R2 ( where Rp is resistance in parallel )

1/Rp = 1/2 + 1/2

1/Rp = 2/2

1/Rp = 1

Rp = 1 ohm.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...