The correct option is (C) 12 h.
Explanation:
T(1/2) = 2 hr.
The radioactive sample decreases to (1 / 2n) in n half lives.
∵ initial activity is 64 times permissible level, it must become (1 / 64)th of its initial value.
∴ (1 / 64) = (1 / 2n)
∴ n = 6
∴ In 6 half lives activity will reduced itself to permissible level.
Given : half life = 2hrs hence total time taken is 6 × 2 = 12 hrs.