The correct option (B) 1.8 × 105V
Explanation:
side of square = √2m
∴ diagonal = 2cm
∴ r = [(diagonal)/2] = 1m
∴ Potential at centre 'o' = (k/r) (Q1 + Q2 + Q3 + Q4)
∴ V = [(9 × 109)/1] [10 ×10–6 + 5 × 10–6 – 3 ×10–6 + 8 × 10–6]
= 9 × 109 [20 × 10–6]
= 180 × 103
∴ V = 1.8 ×105 V