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asked in JEE by (49 points)
  • circle
  • hyperbola
  • straight line
  • parabola

1 Answer

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answered by (33.4k points)
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Best answer

x + 2ay + a = 0 (1) 

x + 3by + b = 0 (2) 

x + 4ay + a = 0  (3) 

As these lines are concurrent , so f we solve any two lines , then intersection point of these two lines will satisfy the third line. 

So take the line (1) and  (2), on solving we get

And pair of straight line equation is : px2+ qy2 + 2hxy = 0 [ here p ,h and q are constant] 

So equation (1) also represent a pair of straight line. 

As the equation will be 4x2+ 6y2- 10xy  = 0  , put (a,b) .

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