Join Sarthaks eConnect Today - Largest Online Education Community!
+1 vote
616 views
in JEE by (54 points)
  • circle
  • hyperbola
  • straight line
  • parabola

1 Answer

+2 votes
by (65.6k points)
selected by
 
Best answer

x + 2ay + a = 0 (1) 

x + 3by + b = 0 (2) 

x + 4ay + a = 0  (3) 

As these lines are concurrent , so f we solve any two lines , then intersection point of these two lines will satisfy the third line. 

So take the line (1) and  (2), on solving we get

And pair of straight line equation is : px2+ qy2 + 2hxy = 0 [ here p ,h and q are constant] 

So equation (1) also represent a pair of straight line. 

As the equation will be 4x2+ 6y2- 10xy  = 0  , put (a,b) .

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...