The correct option (A) 1A
Explanation:
This can be reduced as 1Ω series with 1Ω hence R = 2Ω
This 2Ω is parallel with 2Ω hence R' = (1/1)Ω
Now R' in series with 2Ω hence R" = 1 + 2 = 3Ω
R" parallel with 6Ω hence R"' = 3Ω || 6Ω
= 2Ω
This R"' & 2Ω in series. hence effective resistance is 2Ω + 2Ω = 4Ω
∴ Total current = I = {(12V)/(4Ω)}
∴ I = 3A
The circuit can be drawn as
at point C, I will get divide as (2I / 3) & (I/3).
further at point D, (2I/3) will get divided equally as (I/3), (I/3)
∴ current through ammeter = (I/3) = (3/3) = 1A