The correct option (B) 7Ω
Explanation:
The circuit can be redrawn as shown.
Let a battery of EMF E is connected as shown.
The current in various branches is as shown.
applying Kirchoff's low to ACDA, CBDC, ADBGFA,
5i2 + 5i3 – 10i1 = 0 (1)
10(i2 – i3) – 5(i1 + i3) – i3 = 0 (2)
10 i1 + 5(i1 + i3) – E (3)
from (1) & (2) i2 = {(3i1)/2} & i3 = (i1/2)
if R is effective resistance between A & B then
R = {E/(i1 + i2)} = {E/(i1 + {(3i1)/2})} = {(2E)/(5i1)}
from eqn (3), E = 15i1 + 5i3
∴ E = 15i1 + 5 × (i1/2)
E = (35/2)i1
∴ R = [{2 × (35/2)i1} / {5i1}] = 7Ω