Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
9.0k views
in Physics by (73.7k points)

The displacement of a particle of a string carrying a traveling wave is given by 

y =(3.0cm)sin6.28(0.50x 50t),

where x is in centimeter and t in second. Find (a) the amplitude, (b) the wavelength, (c) the frequency and (d) the speed of the wave.

1 Answer

+1 vote
by (69.1k points)
selected by
 
Best answer

In a open organ pipe the frequency of the wave is  n= Vt/λ  where Vt is the velocity of wave at temperature t and λ=2L is the wavelength of the vibrating wave. If temperature of air inside the organ pipe changes, the velocity of wave also changes, since V∝ T.

On comparing with the standard wave equation

we see that, Amplitude = A = 3.0 cm

Wavelength = λ=1/0.50 cm = 2.0 cm, and the frequency

The speed of the wave is V =νλ

= (50 s-1) (2.0cm) = 100 cm s-1

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...