Question

Write a function to return the second largest number from a list of numbers.

Answer 1

Program:

def secLargestNum(list1):

#Sorting the list in ascending order

list1.sort()

#Returning the second last index of list1

#List with negative indexing will start from the end in reverse order with -1 as

the index of the last element

secondLast = list1[-2]

#or len(list1)-2 can be used which will return second last element

​#secondLast = list1[len(list1)-2]

return secondLast

list1 = [1, 2, 3, 4, 5, 6, 7, 8, 9]

#Using secLargestNum function to get the function

sec_num = secLargestNum(list1)

#Printing all the elements for the list

print("The elements of the list",list1)

#Printing the second largest num

print("\nThe second-largest number of the list:",sec_num)

OUTPUT:

The elements of the list [1, 2, 3, 4, 5, 6, 7, 8, 9]

The second-largest number of the list: 8