Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
13.1k views
in Physics by (72.3k points)

2g of O2 gas is taken at 27°C and pressure 76 mm Hg. Find out volume of gas (ln liter) 

(A) 3.08 

(B) 44.2 

(C) 2.05 

(D) 2.44

1 Answer

0 votes
by (71.4k points)
selected by
 
Best answer

Correct option: (C) 2.05

Explanation:

PV = nRT = (m / mo) RT

∴ V = (m / mo) (RT / P)

Here   m = mass of O2 = 2 gm

mo = molar mass = 32 gm

  V = (2 / 32) × [{8.31 × (273 + 27)} / {76 × 10–3}]

= 2.05 × 103 m3 

= 2.05 liter

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...