Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
4.2k views
in Mathematics by (69.2k points)
edited by

If  5p2 - 7p - 3 = 0 and 5q2 - 7q - 3 = 0,  p ≠ q , then the equation whose roots are 5p– 4q and 5q – 4p is :

(A)   5x2 + x - 439 = 0

(B)   5x2 + 7x - 439 = 0

(C)   5x2 - 7x - 439 = 0

(D)   5x2 + 7x + 439 = 0

1 Answer

+2 votes
by (73.2k points)
selected by
 
Best answer

Correct option  (C) 5x2 - 7x - 439 =  0

Explanation:

Obviously p,q satisfy the equation 5x2 - 7x - 3 =  0.

Hence  p + q = 7/5, pq = -3/5

given α = 5p - 4q & β = 5q - 4p.

The required equation

x2 - (α + β) x + αβ = 0

5x2 + 7x - 439 =  0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...