A charge of 0.8 couloumb is devided into two charges Q &R. These are kept at a seperation of 30 cm. The force Q is maximum when

Question

A)Q=R=0.4

B)Q=0.8C, R negligible

C)Q negligible, R=0.8

D)Q=0.2, R=0.6

Answer 1

We know from the Coulomb's law that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects. In equation form, Coulomb's law can be stated as

F = kQ₁Q₂/d²

Where Q1 represents the quantity of charge on object 1 (in Coulombs), Q2 represents the quantity of charge on object 2 (in Coulombs), and d represents the distance of separation between the two objects (in meters). The symbol k is a proportionality constant known as the Coulomb's law constant. The value of this constant is dependent upon the medium that the charged objects are immersed in. 

So from given question,So the option B is correct

Comments

i cant understand