Given a triangle whose vertices are at \( (0,0),(4,4) \) and \( (10,0) \). A square is drawn in it such that its base is on the \( x \)-axis and its two comers are on the 2 sides of the triangle. The area of the square is equal to
(A) \( \frac{400}{49} \)
(B) \( \frac{400}{25} \)
(C) \( \frac{625}{16} \)
(D) \( \frac{625}{49} \)