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in Co-ordinate geometry by (15 points)
Given a triangle whose vertices are at \( (0,0),(4,4) \) and \( (10,0) \). A square is drawn in it such that its base is on the \( x \)-axis and its two comers are on the 2 sides of the triangle. The area of the square is equal to (A) \( \frac{400}{49} \) (B) \( \frac{400}{25} \) (C) \( \frac{625}{16} \) (D) \( \frac{625}{49} \)
by (15 points)
400/49 is the right answer for this question

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1 Answer

+1 vote
by (48.8k points)

Correct option is (A) \(\frac{400}{49}\)

Area of PQRS = ar(OBC) − ar(BPQ) − ar(OPS) − ar(QRC)

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