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De-Broglie wavelength of electron in nth Bohr orbit is……

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De-Broglie wavelength of electron in nth Bohr orbit is…… 

(A) {(2πr) / n} Å 

(B) 2πrm Å 

(C) (1/n) Å 

(D) nÅ

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1 Answer

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Best answer

The correct option is (A) {(2πr) / n} Å.

Explanation:

According to de Broglie concept whole number of wavelength must fit around the circle. Hence for circumference must be equal to nλ. 

∴ 2πr = nλ 

∴ λ = {(2πr) / n} Å

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