Correct option is (c) Same on both the planets.
Let mass of the object is m, weight of the object on planet A is
\(w_A = \frac{GM_Am}{R_A^2}\)
where, MA and RA are mass and radius of planet A, respectively.
Similarly, weight on planet B is
\(w_B = \frac{GM_Bm}{R_B^2}\)
\(\therefore \frac{w_A}{w_B} = \frac{M_A}{M_B} \times \left(\frac{R_B}{R_A}\right)^2\)
\(= 4 \times (\frac 12)^2 \)
\(=1\)
⇒ \(w_A = w_B\) \((\therefore M_A = 4 M_B \text{ and } R_A = 2R_B)\)