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An unbiased dice with faces 1,2,3,4,5 and 6 is round 4 times. Out of four face values obtained the probability that the minimum face value obtained the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 is 

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When we roll a die for 4 time total cases are: 6 × 6 × 6 × 6

Favored cases are when we got numbers: 2, 3, 4, 5 = 4 numbers 

Probability for this case = \(\frac{4\times 4 \times 4 \times 4}{6 \times 6 \times 6 \times 6}\)

\(= \frac{16}{81}\)

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