5,-25 , 125, -625, 3125
the first term \(a_{1}=5\)
the second term \(a_{2}=-25\)
the common ration \(r= \frac{a_{2}}{a_{1}}\)
\(r=\frac{-25}{5}=-5\)
the given series a G.P
the nth term of a G.P is given by \(a_{n}=ar^{n-1}\)
here to find 6th term (n=6)
\(a_{6}=5(-5)^{6-1}\)
\(a_{6}=5(-5)^{5}\)
\(a_{6}=-15625\)
