Question

Two particles A and B of masses m_A and m_B respectively and having the same charge are moving in a plane. A uniform mag. field exists perpendicular to this plane. The speeds of the particles are V_A and V_B respectively and the trajectories are as shown in the figure, then.

(a) m_AV_A < m_BV_B 

(b) m_AV_A > m_BV_B

(c) m_A < m_B & V_A > V_B 

(d) m_A = m_B & V_A = V_B

Answer 1

The correct option (b) m_AV_A > m_BV_B

Explanation:

We know r = (mV/qB)

Both particles have same charge and uniform magnetic field

Hence r ∝ mV

As r_A > r_B ……..as shown in figure

Hence m_AV_A > m_BV_B