Correct option is (b) -6
Given, \(\vec a = 2\hat i + 4\hat j+3\hat k\)
and \(b = \hat i + \hat j - 4\hat k\)
So scalar product
\(\vec a. \vec b = (2\hat i + 4\hat j+ 3\hat k)(\hat i + \hat j - 4\hat k)\)
\(= 2(1) +4(1)- 12(1)\)
\(= 2 + 4 -12\)
\(= 6 - 12\)
\(=-6\)