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Let (1 + 2x)^20 = a0 + a1x + a2 x^2 + .... + a20x^20. Then, 3a0 + 2a1 + 3a2 + 2a3 + 3a4 + 2a5 + .... 2a19 + 3a20 equals to :

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Let (1 + 2x)20 = a0 + a1x + a2 x2 + .... + a20x20. Then, 3a0 + 2a1 + 3a2 + 2a3 + 3a4 + 2a5 + .... 2a19 + 3a20 equals to :

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Correct option: (c)

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